What is the displacement for the following vectors?
A vector moving 45 degrees northeast at a velocity of 3m/s and turns 30 degrees southeast
Displacement involves velocity and time. Your question is most incomplete.
Bob tupeleko ipalileko kaili so that tukopeko mailo ni due date ifwe.
To find the displacement for the given vectors, we can break down the information given and calculate the resultant displacement.
1. Vector moving 45 degrees northeast at a velocity of 3 m/s:
- This vector can be represented as a right-angled triangle with the vertical component representing the north direction and the horizontal component representing the east direction.
- To find the horizontal and vertical components, we can use trigonometry. The angle of 45 degrees can be divided into two right-angled triangles, each with an angle of 45 degrees.
- The vertical component will be the sine of 45 degrees multiplied by the velocity: sin(45°) * 3 m/s.
- The horizontal component will be the cosine of 45 degrees multiplied by the velocity: cos(45°) * 3 m/s.
2. The vector turns 30 degrees southeast:
- This means that the vector changes its direction by moving 30 degrees in the southeast direction.
- However, we already have the vertical and horizontal components calculated from the previous step, so we need to adjust these components based on the new direction.
- Since the vector turns 30 degrees southeast, we need to subtract 30 degrees from the original angle of the vector.
- Then, we recalculate the vertical and horizontal components based on the adjusted angle.
Finally, we can find the displacement by summing up the final vertical and horizontal components. The displacement is a vector quantity, so it includes both magnitude (length) and direction. We can use the Pythagorean theorem to find the magnitude and trigonometry to find the direction.