Draw the product of the reaction:
CH3CH2CH (double bond) CH2 + Cl2
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CH3CH2CHClCH2Cl
To draw the product of the reaction between CH3CH2CH=CH2 and Cl2, we first need to understand the type of reaction. In this case, it is a reaction called addition, where the double bond in the starting molecule is broken, and the new atoms are added to each side of the double bond.
Step 1: Identify the reactants:
CH3CH2CH=CH2 (1-butene) + Cl2 (chlorine)
Step 2: Break the double bond and add atoms to both sides:
The Cl2 molecule will break into two Cl atoms, where each Cl atom will attach to each side of the double bond in 1-butene.
So, the product will be:
CH3CH2CH(Cl)-CH2-CH2(Cl)
To draw the product of the reaction between CH3CH2CH=CH2 (1-butene) and Cl2, we need to understand the mechanism of the reaction.
The reaction you have mentioned is a typical example of a halogenation reaction, specifically, the reaction of an alkene with a halogen.
Here's a step-by-step explanation of how to draw the product:
Step 1: Identify the reactants: CH3CH2CH=CH2 (1-butene) and Cl2 (chlorine).
Step 2: Determine the type of reaction: This is a halogenation reaction, which involves the addition of a halogen to an alkene.
Step 3: Determine the reaction mechanism: In the presence of light or heat, the chlorine molecule will undergo homolytic cleavage, forming two chlorine radicals.
Step 4: Radical initiation: One chlorine radical will react with another chlorine molecule, forming two more chlorine radicals. This step generates the radicals needed for the reaction to proceed.
Step 5: Radical propagation: The chlorine radical will attack the double bond in 1-butene, forming an allylic radical intermediate.
Step 6: Radical termination: Finally, the allylic radical intermediate will react with a chlorine radical, resulting in the substitution of one of the hydrogen atoms on the allylic carbon with a chlorine atom.
The product of this reaction is 1-chlorobutane (CH3CH2CH2CH2Cl), which is formed by replacing one of the hydrogen atoms on the allylic carbon (adjacent to the double bond) with a chlorine atom.
Hence, the drawn product is CH3CH2CH2CH2Cl.