What value of c makes x^2 + 6x + c a perfect square trinomial?
3
6
9
12
To determine the value of c that makes the trinomial a perfect square, we need to find the square of half the coefficient of the x-term.
Given the trinomial x^2 + 6x + c, the coefficient of the x-term is 6.
The square of half the coefficient of the x-term is (6/2)^2, which simplifies to 3^2, which is 9.
Therefore, the value of c that makes the trinomial a perfect square is 9.
To determine the value of c that makes the trinomial x^2 + 6x + c a perfect square, we need to use a specific method.
Step 1: Identify the coefficient of the x term, which is 6.
Step 2: Take half of this coefficient and square it. Half of 6 is 3, so 3^2 = 9.
Step 3: The value of c that makes the trinomial a perfect square is the square obtained in Step 2, which is 9.
Therefore, the value of c that makes x^2 + 6x + c a perfect square trinomial is 9.