An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 8305 J. What is the specific heat of the gas?
I showed you how to do this last night Sam.
Yo yo honey Singh
To find the specific heat of the gas, we need to make use of the formula:
Q = mc∆T
where:
Q is the heat energy transferred,
m is the mass of the substance,
c is the specific heat capacity of the substance,
∆T is the change in temperature.
In this case, we're given the mass of the gas which is 80.0 grams, the change in temperature which is (225 °C - 25 °C) = 200 °C, and the energy transferred which is 8305 J.
Now, from the given information, we can calculate the heat energy:
Q = mc∆T
8305 J = (80.0 g) × c × (200 °C)
To find the specific heat, c, we divide both sides of the equation by (80.0 g × 200 °C):
c = 8305 J ÷ (80.0 g × 200 °C)
Now, we can substitute the given values and calculate the specific heat:
c ≈ 0.519 J/g·°C
Therefore, the specific heat of the gas is approximately 0.519 J/g·°C.