two blocks (a and b) are in contact on a horizontal frictionless surface. a 60N constant horizontal force is applied to A. the mass of a is 3.0 kg and the mass of b is 15 kg. what is the magnitude of the force of a on b
To find the magnitude of the force of A on B, we need to consider Newton's third law of motion, which states that every action has an equal and opposite reaction.
Here's how you can calculate it:
Step 1: Determine the acceleration of the system.
Since the force applied on A is horizontal and constant, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration (Fnet = ma).
Fnet = 60 N (the applied force on A)
Mass of A = 3.0 kg
Mass of B = 15 kg
Since the blocks are in contact and there is no friction, they will have the same acceleration.
Fnet = (Mass of A + Mass of B) x acceleration
Plugging in the values:
60 N = (3.0 kg + 15 kg) x acceleration
Step 2: Solve for acceleration.
60 N = 18 kg x acceleration
Divide both sides by 18 kg:
acceleration = 3.33 m/s²
Step 3: Calculate the force of A on B.
Now that we have the acceleration of the system, we can find the force of A on B by multiplying the mass of B by the acceleration.
Force of A on B = mass of B x acceleration
Plugging in the values:
Force of A on B = 15 kg x 3.33 m/s²
Multiply the values:
Force of A on B = 49.95 N
Therefore, the magnitude of the force of A on B is 49.95 N.
To find the magnitude of the force of block A on block B, we can use Newton's third law, which states that the force exerted by object A on object B is equal in magnitude and opposite in direction to the force exerted by object B on object A.
In this case, we can assume that the force applied to block A is transmitted to block B. Therefore, the magnitude of the force of A on B is equal to the force applied to block A.
So, the magnitude of the force of A on B is 60N.
the blocks accelerate at
... 60/18 = 10/3 m/s^2
the force necessary for b
... 15 * 10/3