driver a is going west at 60 mph driver b leaves 3 hours later at a rate of 72 mph how long until driver b catches up to driver A
in 3 hours, A is 180 miles ahead.
B is going 12 mi/hr faster, so how long to make up the 180 miles?
60t=72(t-3) 60t=72t-216
-12t=-216 t=18 t-3=15
The answer is 15hrs
To determine how long it will take for Driver B to catch up to Driver A, you need to find the time at which they meet.
First, you need to determine the distance that Driver A traveled during the 3 hours when Driver B was not yet on the road. This can be calculated using the formula: distance = rate × time.
Distance covered by Driver A = 60 mph × 3 hours = 180 miles.
Now, let's set up an equation to find when Driver B catches up to Driver A. We know that Driver B is traveling at a rate of 72 mph, and Driver A has a head start of 180 miles.
Let's assume it takes x hours for Driver B to catch up to Driver A. During this time, Driver A continues to drive at a rate of 60 mph, and Driver B is traveling at 72 mph.
Distance covered by Driver B = Distance covered by Driver A + Head Start
72 mph × x hours = 60 mph × (x + 3 hours) + 180 miles
Simplifying this equation, we have:
72x = 60(x + 3) + 180
Now, solve for x:
72x = 60x + 180 + 180
72x - 60x = 360
12x = 360
x = 360 / 12
x = 30
Therefore, it will take Driver B 30 hours to catch up to Driver A.