How to prepare 250ml of 2.5m solution of HCL
If you REALLY want 2.5 m (m means molal, not molar), then dissolve 2.5/4 mol HCl in 0.250 L H2O. The resulting solution may or may not be 250 mL.
If you want 2.5 M (molar) and I suspect you do, then dissolve 2.5/4 mol HCl in some water and make to a total volume of 250 mL.
To prepare a 250ml solution of 2.5M HCl, you will need to know the molar mass of HCl and the desired concentration.
Step 1: Calculate the amount of HCl needed.
The molar mass of HCl is the sum of the atomic masses of hydrogen (H) and chlorine (Cl), which is approximately 36.5 grams/mol.
First, we need to calculate the number of moles of HCl required. We can use the formula:
Moles = concentration (M) × volume (L)
Since the volume is given in ml, we need to convert it to liters:
Volume = 250 ml = 250/1000 L = 0.25 L
Now, we can calculate the moles of HCl:
Moles = 2.5 M × 0.25 L = 0.625 moles
Step 2: Calculate the mass of HCl needed.
Using the moles of HCl calculated in step 1 and the molar mass of HCl:
Mass = moles × molar mass
Mass = 0.625 moles × 36.5 g/mol ≈ 22.81 grams
Therefore, you will need approximately 22.81 grams of HCl to prepare 250ml of a 2.5M solution.