station A and station B apart from rest st station A and acceleration at A constants rate of a=1.2 m.s.s

until the mid point to station B it slows down at the same rate a and stop at b final?
a) the time of train between station ?
b)The maximum speed of the train?

You want to specify all the data and try again?

and that's m/s^2, not some bogus m.s.s which is meaningless.

To find the answers to these questions, we can use the equations of motion.

a) The time taken by the train to travel between stations A and B can be found by dividing the total distance by the average velocity. Since the train starts with a constant acceleration at A and slows down until it stops at B, we can find the average velocity as the average of the initial and final velocities.

To find the distance between the stations, we need more information. If you provide the distance between stations A and B, we can proceed with the calculation.

b) The maximum velocity of the train can be found using the equation:

v^2 = u^2 + 2as

Where:
v = final velocity (maximum velocity of the train)
u = initial velocity
a = acceleration
s = distance traveled

Since the train starts with an initial velocity of 0 at A and has a constant acceleration, we can use the above equation to calculate the maximum velocity. However, we again need the distance between stations A and B to proceed with the calculation.

Please provide the distance between stations A and B, and I will be able to provide you with the answers.