The pressure of water on the ground floor is 40,000 Pascal, and at the first floor is 10,000 pascal. Find the height of the first floor.

P=40000-10000

.... therefore.. P= hdg
So,30000=h*1000*10
Thus.....h =30000/10000
Therefore h= 3 m

Why we have subtracted 10000 from 40000

Because there is change in height...

To find the height of the first floor, we can use the formula for pressure:

Pressure = Density × gravity × height

Given that the pressure on the ground floor (P1) is 40,000 Pascal and the pressure on the first floor (P2) is 10,000 Pascal, we can set up the following equation:

P1 = ρ × g × h1
P2 = ρ × g × h2

Where ρ is the density of water (approximately 1,000 kg/m^3) and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Since the density and gravity are the same in both equations, we can cancel them out. Let's divide the two equations to eliminate them:

P1/P2 = h1/h2

Now we can plug in the given values:

40,000/10,000 = h1/h2

Simplifying:

4 = h1/h2

Therefore, the height of the first floor (h2) is four times the height of the ground floor (h1).

So, if the height of the ground floor is "x" meters, the height of the first floor will be "4x" meters.

P1-P2=30000=height×density×acceleration due to gravity.

i.e, 30000=h×1000×10
30000=h×10000
So,h=30000÷10000
h=3metre