A chemist reacted 0.05 mol of sodium with water to form 50cm3 of sodium hydroxide what was the mass of sodium reacted
Na+h2p-Noah+h2
2Na + 2H2O ==> 2NaOH + H2
mols Na = 0.05.
g Na = mols Na x atomic mass Na = ?
1.15gm
To determine the mass of sodium reacted, we'll need to use the balanced chemical equation for the reaction between sodium and water:
2Na + 2H2O -> 2NaOH + H2
From the equation, we can see that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas.
Given that you reacted 0.05 mol of sodium and obtained 50 cm3 of sodium hydroxide, we can calculate the mass of sodium reacted using the molar mass of sodium.
1. Calculate the number of moles of sodium hydroxide produced:
Using the equation, the molar ratio between sodium and sodium hydroxide is 2:2, which means equal numbers of moles. Hence, 0.05 mol of sodium will produce 0.05 mol of sodium hydroxide.
2. Calculate the molar mass of sodium hydroxide (NaOH):
Na: 22.99 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol
3. Calculate the mass of sodium hydroxide:
Mass of sodium hydroxide = molar mass × number of moles
Mass of sodium hydroxide = 40.00 g/mol × 0.05 mol
Mass of sodium hydroxide = 2.00 g
4. Calculate the mass of sodium reacted:
Since sodium hydroxide has a 1:1 molar ratio with sodium, the mass of sodium reacted is the same as the mass of sodium hydroxide, which is 2.00 g.
To determine the mass of sodium that reacted, you can use the molar ratio between sodium and sodium hydroxide. The balanced equation for the reaction is:
2Na + 2H2O -> 2NaOH + H2
From the equation, it can be seen that 2 moles of sodium (Na) react to produce 2 moles of sodium hydroxide (NaOH).
Given that the chemist reacted 0.05 moles of sodium, we can use the molar ratio to find the number of moles of sodium hydroxide produced.
0.05 moles of Na * (2 moles of NaOH / 2 moles of Na) = 0.05 moles of NaOH
Now, we need to convert the moles of sodium hydroxide to grams by utilizing its molar mass. The molar mass of NaOH is 22.99 g/mol for sodium, plus 16.00 g/mol for oxygen, and 1.01 g/mol for hydrogen.
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol
To find the mass, we can multiply the number of moles of NaOH by its molar mass:
0.05 moles of NaOH * 40.00 g/mol = 2.00 grams
Therefore, the mass of sodium that reacted is 2.00 grams.