A motor car travelling at 14m/s on dry flat surface should be able to stop in 14m.Assuming the deceleration to be uniform.
Given: its value and the corresponding bracking time is -7m/s^2 , 2 sec
Calculate the distance travelled during the first second after the application of the brakes.
V = Vo + a*t = 14 - 7*1 = 7 m/s.
V^2 = Vo^2 + 2a*d.
7^2 = 14^2 - 14*d, d = ?.
To calculate the distance traveled during the first second after the application of the brakes, we need to use the equation of motion:
Distance = Initial velocity * Time + (1/2) * Acceleration * Time^2
Given:
Initial velocity (u) = 14 m/s (please note that being the initial velocity, it is positive)
Acceleration (a) = -7 m/s^2 (negative sign indicates deceleration)
Time (t) = 1 sec (as we want to calculate the distance traveled during the first second)
To solve the equation, we substitute the given values:
Distance = 14 * 1 + (1/2) * (-7) * (1^2)
Distance = 14 - 3.5
Distance = 10.5 meters
Therefore, the distance traveled during the first second after the application of the brakes is 10.5 meters.