Given: 11-pound mixture of peanuts, almonds, and raisins
Cost:
peanuts - 1.5 per pound
almonds - 3 per pound
raisins - 1.5 per pound
mixture:
twice as many peanuts as almond; total cost of mixture is 21.
a + p + r = 11 lbs
a + 2a + r = 11 lbs
3a + r = 11
r = 11 - 3a
1.5(2a) + 3a + 1.5r = 21
3a + 3a + 1.5r = 21
6a + 1.5r = 21
6a + 1.5(11-3a) = 21
6a + 16.5 - 4.5a = 21
6a - 4.5a = 21 - 16.5
1.5a = 4.5
1.5a/1.5 = 4.5/1.5
a = 3
almonds = 3 lbs
peanuts = 2a = 2(3) = 6lbs
raisins = 11 - 3a = 11 - 3(3) = 11 - 9 = 2 lbs
My answer is: C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins
1.)(-5,-1,0)
2.)(-8,-7,5)
3.)(6lbs peanuts,3lbs almonds,2lbs raisins)
anonymous is correct!
what's the answer to the rest of the quiz???
#1 is -5,-1,0
You can easily check this yourself.
First
3 + 6 + 2 = 11 sure enough
twice as many peanuts as almonds, yes
total cost = 1.5*6 + 3*3 + 1.5*2
= 9 + 9 + 3 = 21 so yes, done
Well, with 6 pounds of peanuts, that's a lot of peanut butter. You could open up your own sandwich shop! And 3 pounds of almonds, that's enough to keep the squirrels happy. As for the 2 pounds of raisins, well, that's just enough to add a little sweetness to your trail mix. Nice job on cracking the nut of this problem!
To solve this problem, we need to use a system of equations. Let's first define the variables:
a = pounds of almonds
p = pounds of peanuts
r = pounds of raisins
From the given information, we know that there are 11 pounds in total, so we have the equation:
a + p + r = 11
We also know that there are twice as many peanuts as almonds, so we have the equation:
p = 2a
Now we can substitute the second equation into the first equation to get:
a + (2a) + r = 11
3a + r = 11
r = 11 - 3a
Now let's consider the cost of the mixture. We know that peanuts cost $1.5 per pound, almonds cost $3 per pound, and raisins cost $1.5 per pound. Therefore, the total cost can be calculated as follows:
1.5p + 3a + 1.5r = 21
Substituting the value of p from the second equation, we get:
1.5(2a) + 3a + 1.5r = 21
3a + 3a + 1.5r = 21
6a + 1.5r = 21
Substituting the value of r from the first set of equations, we get:
6a + 1.5(11-3a) = 21
6a + 16.5 - 4.5a = 21
6a - 4.5a = 21 - 16.5
1.5a = 4.5
a = 4.5/1.5
a = 3
Therefore, the solution is a = 3. Substituting this value back into the second equation, we get:
p = 2a = 2(3) = 6
Substituting the values of p and a back into the first equation, we get:
r = 11 - 3a = 11 - 3(3) = 11 - 9 = 2
Therefore, the answer is C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins.