a blacksmith has a rectangular iron sheet with the length of 10 cm. he has to cut out 7 circular disc of radius 1 cm. what is the minimum width of that rectangular sheet?
To find the minimum width of the rectangular sheet, we need to consider the space needed for the circular discs.
Each circular disc has a diameter of 2 cm (since the radius is 1 cm), and we need to cut out 7 such discs. So, the total width occupied by the discs would be:
Total width occupied by the discs = diameter of one disc * number of discs
= 2 cm * 7
= 14 cm
Now, we need to add some extra width to the total width occupied by the discs to give the blacksmith enough room to cut them out.
Let's assume we add an extra width of 1 cm on each side of the row of discs. So, the total width of the rectangular sheet would be:
Total width of the rectangular sheet = total width occupied by the discs + extra width on each side
= 14 cm + 1 cm + 1 cm
= 16 cm
Therefore, the minimum width of the rectangular sheet should be 16 cm.
To find the minimum width of the rectangular sheet, we need to consider the space required for the circular discs.
The diameter of each circular disc can be calculated as twice the radius, which means the diameter of each disc is 2 cm.
Since the diagonal of the rectangular sheet must be greater than or equal to the combined diameters of the circular discs, we can calculate the minimum width by adding the diameter of each circular disc:
Total diameter of 7 circular discs = 7 * 2 cm = 14 cm
Now, assuming that the width of the rectangular sheet is minimum, the width will be equal to the diameter of the circular discs, which is 14 cm.
So, the minimum width of the rectangular sheet is 14 cm.
3.4 minimum width
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