How many grams of glucose are needed to form 150g of ethanol?
To answer this question, we need to know the molar mass of glucose and ethanol.
The molar mass of glucose (C6H12O6) is calculated by adding up the atomic masses of its constituent elements:
(6 × (12.01 g/mol)) + (12 × (1.01 g/mol)) + (6 × (16.00 g/mol)) = 180.18 g/mol
The molar mass of ethanol (C2H5OH) is calculated by adding up the atomic masses of its constituent elements:
((2 × (12.01 g/mol)) + (6 × (1.01 g/mol))) + (16.00 g/mol) = 46.07 g/mol
Using these molar masses, we can calculate the number of moles of ethanol in 150 g of ethanol:
Number of moles of ethanol = mass of ethanol / molar mass of ethanol = 150 g / 46.07 g/mol ≈ 3.25 mol
Since the balanced chemical equation for the formation of ethanol from glucose is:
C6H12O6 → 2 C2H5OH + 2 CO2
We can see that 1 mole of glucose will produce 2 moles of ethanol. Therefore, to form 3.25 moles of ethanol, we would need:
Number of moles of glucose = (3.25 mol ethanol) / (2 mol glucose) ≈ 1.63 mol
Finally, we can calculate the mass of glucose needed to form 150 g of ethanol:
Mass of glucose = number of moles of glucose × molar mass of glucose
= (1.63 mol) × (180.18 g/mol) ≈ 294 g
Therefore, approximately 294 grams of glucose are needed to form 150 grams of ethanol.
To determine how many grams of glucose are needed to form 150g of ethanol, we first need to know the chemical equation for the reaction between glucose and ethanol.
The chemical equation for this reaction can be represented as:
C6H12O6 → 2C2H5OH + 2CO2
From the equation, we can see that one molecule of glucose (C6H12O6) produces two molecules of ethanol (2C2H5OH) and two molecules of carbon dioxide (2CO2).
To calculate the amount of glucose needed, we first need to determine the molar mass of glucose. The molar mass of glucose (C6H12O6) is calculated as follows:
(6 * atomic mass of carbon) + (12 * atomic mass of hydrogen) + (6 * atomic mass of oxygen)
= (6 * 12.01) + (12 * 1.01) + (6 * 16.00)
= 180.18 g/mol
Next, we need to find the molar mass of ethanol (C2H5OH). The molar mass of ethanol is calculated as follows:
(2 * atomic mass of carbon) + (5 * atomic mass of hydrogen) + (1 * atomic mass of oxygen)
= (2 * 12.01) + (5 * 1.01) + 16.00
= 46.08 g/mol
Now, using the balanced equation, we can determine the molar ratio between glucose and ethanol. From the equation, we can see that 1 mole of glucose produces 2 moles of ethanol.
Given that we have 150g of ethanol, we can calculate the amount of glucose needed using the following steps:
1. Calculate the number of moles of ethanol:
Number of moles = Mass of ethanol / Molar mass of ethanol
= 150 / 46.08
≈ 3.25 moles
2. Calculate the number of moles of glucose needed:
Number of moles of glucose = Number of moles of ethanol * (1 mole of glucose / 2 moles of ethanol)
= 3.25 * (1/2)
= 1.625 moles
3. Convert the number of moles of glucose into grams:
Mass of glucose = Number of moles of glucose * Molar mass of glucose
= 1.625 * 180.18
≈ 293 grams
Therefore, approximately 293 grams of glucose are needed to form 150 grams of ethanol.
C6H12O6 → 2C2H5OH + 2CO2
mols ethanol needed = grams/molar mass
Using the coefficients in the balanced equation, convert mols ethanol to mols glucose
Now convert mols glucose to grams. g = mols x molar mass = ? Post your work if you get stuck.