A team plays 120 matches each year. In it's first year, the team won 45% of it's matches. The next year the team won 55% of it's matches. How many more games did the team win in the 2nd year than in the first year?
it won 10% more.
What is 10% of 120?
108?
no, that's 90%
You want .55*120 - .45*120 = 0.10*120
To find out how many more games the team won in the second year than in the first year, we need to determine the number of games won in each year and then subtract the number of games won in the first year from the second year.
In the first year, the team won 45% of 120 matches. To find the number of games won, we multiply 45% by 120:
Number of games won in the first year = 0.45 * 120 = 54
In the second year, the team won 55% of 120 matches. Similarly, we calculate the number of games won:
Number of games won in the second year = 0.55 * 120 = 66
To find the difference, we subtract the number of games won in the first year from the number of games won in the second year:
Number of games won in the second year - Number of games won in the first year = 66 - 54 = 12
Therefore, the team won 12 more games in the second year than in the first year.