if the density of 2-butanol is 0.80g ml-1, what volume of 2-butanol would be produced from 1kg of butene
To find the volume of 2-butanol produced from 1 kg of butene, we need to know the molar masses of butene and 2-butanol.
The molar masses are:
- Butene (C4H8): 4(12.01) + 8(1.01) = 56.11 g/mol
- 2-Butanol (C4H10O): 4(12.01) + 10(1.01) + 16.00 = 74.12 g/mol
Next, we can calculate the number of moles of butene in 1 kg:
- Moles of butene = mass of butene / molar mass of butene
- Moles of butene = 1000 g / 56.11 g/mol = 17.81 mol
Since the equation for the reaction is not provided, we will assume that the reaction proceeds without any loss or gain of mass.
From the balanced reaction, we can see that 1 mole of butene gives 1 mole of 2-butanol. Therefore, the number of moles of 2-butanol produced is also 17.81 mol.
Finally, we can calculate the volume of 2-butanol using its density:
- Volume of 2-butanol = mass of 2-butanol / density of 2-butanol
- Mass of 2-butanol = moles of 2-butanol x molar mass of 2-butanol
- Mass of 2-butanol = 17.81 mol x 74.12 g/mol = 1,319.95 g
- Volume of 2-butanol = 1,319.95 g / 0.80 g/ml = 1,649.94 ml
Therefore, 1 kg of butene would produce approximately 1,649.94 ml (or 1.65 L) of 2-butanol.