A metal x with relative atomic mass of 56forms an oxide with formul X2O3 .How many grams of the metals will combine with 10g of oxygen
Ethane burns completely in oxygen according to the equations below
C2H6+7¡2O2~2CO +3H2O what is the amount in moles of carbon (iv)oxide will be produced when 6•0g of ethane are completely burnt in oxygen
4X + 3O2>>2X2O3
well, four moles of X will react with three moles of O2.
moles O2= 10g/32g= 10/32
so we need 4/3 of 10/32 or
40/96 moles of X. What is the mass of that? 56*40/96
Your school subject seems to be chemistry.
IT IS QUIT CORRECT
To determine the grams of metal that will combine with 10g of oxygen, we need to use stoichiometry.
First, let's find the molar mass of the metal (X). The relative atomic mass of X is given as 56, which can be interpreted as the molar mass in grams per mole.
Next, let's calculate the number of moles of oxygen using its molar mass. Oxygen has a molar mass of 16g/mol. So, 10g of oxygen is equal to 10g / 16g/mol = 0.625 mol.
According to the formula X2O3, one mole of the metal (X) combines with three moles of oxygen (O). So, the number of moles of metal (X) can be calculated using the equation:
moles of X = (moles of O) / 3
moles of X = 0.625 mol / 3 = 0.208 mol
Finally, to convert moles of X to grams, we can use the molar mass of X (56g/mol):
grams of X = (moles of X) * (molar mass of X)
grams of X = 0.208 mol * 56g/mol = 11.648g
Therefore, approximately 11.648 grams of the metal (X) will combine with 10 grams of oxygen.
Regarding the second question, let's find the amount in moles of carbon (IV) oxide (CO2) produced when 6.0 grams of ethane (C2H6) is completely burned in oxygen.
From the balanced equation:
C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
We can see that for every 1 mole of ethane (C2H6), 2 moles of carbon dioxide (CO2) are produced. The molar mass of ethane is 30 g/mol, so we need to convert the given mass into moles:
moles of C2H6 = (given mass of C2H6) / (molar mass of C2H6)
moles of C2H6 = 6.0 g / 30 g/mol = 0.2 mol
From the equation, we can now determine the moles of carbon dioxide produced:
moles of CO2 = (moles of C2H6) * (moles of CO2 / mole of C2H6)
moles of CO2 = 0.2 mol * (2 mol CO2 / 1 mol C2H6) = 0.4 mol
Therefore, 0.4 moles of carbon (IV) oxide (CO2) will be produced when 6.0 grams of ethane are completely burnt in oxygen.