7/x^2-8 does it give you 7ln(x^2-8)
no. if u = x^2-8, du = 2x dx
You need an x in the numerator.
Instead, use partial fractions.
x^2-8 = (x+√8)(x-√8)
You will wind up with logs of those factors.
You need an x in the numerator.
Instead, use partial fractions.
x^2-8 = (x+√8)(x-√8)
You will wind up with logs of those factors.