Carla had twice as much money as Vida. After carla gave 12 pesos to vida,carla still had 10 pesos more than vida. how much was the total money of the 2 girls in the beginning?

c=2v

c-12 = v+12 + 10

2v-12 = v+22
v = 34
c = 68
...

Let's assume that Vida had x pesos in the beginning.

According to the given information, Carla had twice as much money as Vida, so Carla had 2x pesos in the beginning.
After Carla gave 12 pesos to Vida, Carla had 2x - 12 pesos, and Vida had x + 12 pesos.
It is also mentioned that Carla still had 10 pesos more than Vida, so Carla's money was 10 pesos greater than Vida's money.
Therefore, we can set up the following equation: 2x - 12 = x + 12 + 10.
Simplifying the equation, we get: x = 34.
Thus, Vida had 34 pesos in the beginning, and Carla had twice as much money, which is 2 * 34 = 68 pesos.
Therefore, the total money of the two girls in the beginning was 34 + 68 = 102 pesos.

To solve this problem, let's break it down step by step.

Let's assume Vida's initial amount of money is denoted by V, and Carla's initial amount of money is denoted by C.

According to the problem, Carla had twice as much money as Vida. So we can write the first equation:

C = 2V --- (Equation 1)

Next, the problem states that Carla gave 12 pesos to Vida, and after that, Carla still had 10 pesos more than Vida. This gives us the second equation:

C - 12 = V + 10 --- (Equation 2)

Now we have two equations, and we can solve them simultaneously to find the values of C and V.

Let's substitute Equation 1 into Equation 2:

2V - 12 = V + 10

Simplifying the equation:

2V - V = 10 + 12
V = 22

Now, we can substitute the value of V (22) into Equation 1 to find C:

C = 2V
C = 2 * 22
C = 44

Therefore, Vida initially had 22 pesos, and Carla initially had 44 pesos.

To find the total money of the two girls in the beginning, we just need to add their initial amounts:

Total money = V + C
Total money = 22 + 44
Total money = 66

So, the total money of the two girls in the beginning was 66 pesos.