Train A left the station traveling 60 miles in 1 hour. 30 minutes later, train B left the same station traveling 75 miles in 1 hour. How many hours will it take for the two trains to meet up?
I know that a formula, D=V*T, might be useful while solving the equation. Thank you!
When B left, A was 30 miles ahead.
B is going 15 mi/hr faster than A.
So, how long does it take to make up the distance?
I'm not sure what to do.
30/15=2 hours?
15/30=0.5 hours?
come on. If you have to go 30 miles, and you go 15 miles each hour, you must surely see that it will take two hours.
If you want to be sure, include the units:
(30 mi) / (15 mi/hr) = 30/15 hr = 2 hr
(15 mi/hr)/(30mi) = 0.5/hr
That means that you cover half the distance per hour. So, it will take 2 hours.
Try to do a sanity check when you are trying to get an answer. You do have some real-life experience to fall back on.
To solve this problem, we can use the formula D = V * T, where D is the distance, V is the velocity (or speed), and T is the time.
Let's break down the problem step by step:
1. Train A traveled 60 miles in 1 hour. So, we know that train A's speed (V) is 60 miles per hour (mph), and the time (T) is 1 hour.
2. Train B left the same station 30 minutes (or 0.5 hours) later. This means that when Train B starts, Train A has already been traveling for 0.5 hours.
3. Train B traveled 75 miles in 1 hour. So, Train B's speed is 75 mph, and the time is 1 hour.
4. Now, we need to find the time it takes for the two trains to meet up, denoted as T.
Since Train B started 0.5 hours after Train A, the time it will take for Train B to meet up with Train A will be T - 0.5 hours.
Now, let's set up the distance equation for both trains:
Distance traveled by Train A = Distance traveled by Train B
V*A * T = V*B * (T - 0.5)
Substituting the known values:
60 * T = 75 * (T - 0.5)
Simplifying the equation:
60T = 75T - 37.5
15T = 37.5
T = 2.5
So, it will take 2.5 hours for the two trains to meet up.
Hope this helps!