The percentage of nitrogen in magnesium nitride is.?

Mg3N2

find the atomic mass of Mg
find the atomic mass of N

percentN=3*atomicmassMg/totalmass

where total mass= 3*atomicmassM+2*atomicmassN

To find the percentage of nitrogen in magnesium nitride, we need to know the chemical formula for magnesium nitride and use its molar masses.

The chemical formula for magnesium nitride is Mg3N2. This means that for every one molecule of magnesium nitride, there are three atoms of magnesium (with a molar mass of 24.31 g/mol each) and two atoms of nitrogen (with a molar mass of 14.01 g/mol each).

To calculate the percentage of nitrogen in magnesium nitride, we need to determine the molar mass of the entire compound.

Molar mass of Mg3N2:
(3 x Molar mass of magnesium) + (2 x Molar mass of nitrogen)
= (3 x 24.31 g/mol) + (2 x 14.01 g/mol)
= 72.93 g/mol + 28.02 g/mol
= 100.95 g/mol

Next, we need to calculate the mass of nitrogen in one molecule of magnesium nitride.

Mass of nitrogen in one molecule of Mg3N2:
2 x Molar mass of nitrogen
= 2 x 14.01 g/mol
= 28.02 g/mol

Finally, we can calculate the percentage of nitrogen in magnesium nitride by dividing the mass of nitrogen by the molar mass of the compound and multiplying by 100.

Percentage of nitrogen in Mg3N2:
(Mass of nitrogen / Molar mass of Mg3N2) x 100
= (28.02 g / 100.95 g) x 100
= 27.8%

Therefore, the percentage of nitrogen in magnesium nitride is approximately 27.8%.