A bag contains 8 green marbles,5 blue marbles, and 4 white marbles,If one marble is drawn from the bag, what is the probability of drawing a white marble and a green marble (on the same draw)

Since you are drawing ONE marble, the prob( white AND green) = 0

That should have been obvious, how can you have a white and a green marble at the same time.
My question to you...
What is the probability if drawing a white OR a green ?

The answer would be 2 by 15

You couldn't have two different answers.

There are 12 white or green marbles
so prob(a white or green) = 12/ 17

To find the probability of drawing a white marble and a green marble on the same draw, we need to determine the total number of marbles in the bag and the total number of favorable outcomes.

The total number of marbles in the bag is the sum of the number of green, blue, and white marbles: 8 + 5 + 4 = 17.

To calculate the total number of favorable outcomes, we need to determine the number of ways to draw a white and a green marble on the same draw. Since we are drawing only one marble, we need to find the number of ways to select one white marble and one green marble.

The number of ways to draw one white marble from the 4 available is 4, and the number of ways to draw one green marble from the 8 available is 8.

Therefore, the total number of favorable outcomes is 4 * 8 = 32.

Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of outcomes: 32 / 17 = 1.88 or approximately 0.188.

So, the probability of drawing a white marble and a green marble on the same draw is 0.188 or 18.8%.