How would you make .25 Liters of a .1 M MgCl2 solution?
How many mols do you want? That's mols = M x L = ?
Then = mols = grams/molar mass. You know mols and molar rmass, solve for grams.
To make a 0.1 M MgCl2 solution with a total volume of 0.25 Liters, you would need to follow these steps:
Step 1: Calculate the amount of MgCl2 needed
- Molarity (M) is defined as the number of moles of solute dissolved in one liter of solution.
- We can start by using the formula: Molarity (M) = moles of solute / volume of solution (in liters)
- Rearranging the formula, moles of solute = Molarity (M) x volume of solution (in liters)
In this case, we want to make a 0.1 M solution with a volume of 0.25 Liters.
Moles of MgCl2 = 0.1 M x 0.25 L = 0.025 moles
Step 2: Convert moles to grams
- The molar mass of MgCl2 can be calculated by adding up the atomic masses of its constituent atoms.
- The atomic mass of Mg = 24.31 g/mol and the atomic mass of Cl = 35.45 g/mol.
- The molar mass of MgCl2 = (24.31 g/mol x 1) + (35.45 g/mol x 2) = 95.21 g/mol
To convert moles to grams, we can use the formula: grams = moles x molar mass
Mass of MgCl2 = 0.025 moles x 95.21 g/mol = 2.38 grams
Step 3: Dissolve the calculated mass in a solvent (water) and make up to the desired volume
- Weigh out 2.38 grams of MgCl2 using a balance.
- Add the MgCl2 to a container (such as a beaker) and dissolve it in a small volume of deionized water.
- Once the MgCl2 is completely dissolved, add enough deionized water to make a total volume of 0.25 Liters.
- Mix the solution thoroughly to ensure uniformity.
Following these steps will allow you to prepare 0.25 Liters of a 0.1 M MgCl2 solution.
To make 0.25 Liters of a 0.1 M MgCl2 solution, you need to follow these steps:
Step 1: Determine the molar mass of MgCl2.
Mg: 24.31 g/mol
Cl: 35.45 g/mol
So, the molar mass of MgCl2 = (24.31 g/mol) + 2 * (35.45 g/mol) = 95.21 g/mol
Step 2: Calculate the number of moles of MgCl2 required.
0.1 M solution means there are 0.1 moles of MgCl2 per liter of solution.
Moles of MgCl2 = Molarity × Volume (in liters)
= 0.1 mol/L × 0.25 L
= 0.025 moles
Step 3: Calculate the mass of MgCl2 required.
Mass (g) = Moles × Molar mass
= 0.025 mol × 95.21 g/mol
= 2.38 g
So, you need 2.38 grams of MgCl2 to make 0.25 Liters of a 0.1 M MgCl2 solution.
Note: To prepare the solution, you would dissolve the calculated mass of MgCl2 (2.38 g) in a container and then add water until the total volume reaches 0.25 Liters.