25cm3 Of 3g Of Hydrated Sodium Trioxocarbonate (iv) Solution (NaCO3XH2O)per 250cm3 Was Neutralized By 13.20cm3 Of 0.16m Hydrochloric Acid Solution. 1) Write The Equation For The Reaction. 2) Calculate The Conc Of The Base In Mol/dm3. 3) Calculate The Molar Mass Of The Base. 4) The Value Of X. 5) The Percentage By Mass Of Water Of Crystallization.
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1) To write the equation for the reaction, we need to understand that sodium trioxocarbonate (iv) reacts with hydrochloric acid to form sodium chloride, carbon dioxide, and water.
The balanced equation for this reaction is:
Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O
2) To calculate the concentration of the base in mol/dm3, we need to use the equation:
c1v1 = c2v2
Where:
c1 = concentration of the acid (0.16 mol/dm3)
v1 = volume of the acid (13.20 cm3)
c2 = concentration of the base (unknown)
v2 = volume of the base (25 cm3)
Rearranging the equation to solve for c2:
c2 = (c1v1) / v2
c2 = (0.16 mol/dm3 * 13.20 cm3) / 25 cm3
First, let's convert the volumes to dm3:
v1 = 13.20 cm3 / 1000 = 0.0132 dm3
v2 = 25 cm3 / 1000 = 0.025 dm3
Now we can substitute the values into the formula:
c2 = (0.16 mol/dm3 * 0.0132 dm3) / 0.025 dm3
Calculate:
c2 = 0.08448 mol/dm3
Therefore, the concentration of the base is 0.08448 mol/dm3.
3) To calculate the molar mass of the base, we can use the equation:
c = n / V
Where:
c = concentration of the base (0.08448 mol/dm3)
n = number of moles of the base (unknown)
V = volume of the base (0.025 dm3)
Rearranging the equation to solve for n:
n = c * V
n = 0.08448 mol/dm3 * 0.025 dm3
Calculate:
n = 0.002112 moles
Now, to find the molar mass, we can use the equation:
Molar mass = Mass / Number of moles
The given mass of the hydrated sodium trioxocarbonate (iv) is 3g, so:
Molar mass = 3g / 0.002112 moles
Calculate:
Molar mass ≈ 1420 g/mol
Therefore, the molar mass of the base is approximately 1420 g/mol.
4) To find the value of X, we need to understand that hydrated sodium trioxocarbonate (iv) contains X moles of water. From the given information, we know that 3g of the compound contains 0.002112 moles. The molar mass of sodium trioxocarbonate (iv) is approximately 142 g/mol.
Using the equation:
Mass of water = Mass of compound - Mass of sodium trioxocarbonate (iv)
Mass of water = 3g - (142 g/mol * 0.002112 moles)
Calculate:
Mass of water ≈ 2.702 g
Since water has a molar mass of 18 g/mol, we can calculate the moles of water:
Moles of water = Mass of water / Molar mass of water
Moles of water = 2.702 g / 18 g/mol
Calculate:
Moles of water ≈ 0.1501 moles
Therefore, the value of X in the compound NaCO3XH2O is approximately 0.1501.
5) To calculate the percentage by mass of water of crystallization, we can use the equation:
Percentage by mass = (Mass of water / Mass of hydrated compound) * 100
From our previous calculations, we found that the mass of water is approximately 2.702 g and the mass of the hydrated compound is 3g.
Plug in the values:
Percentage by mass = (2.702 g / 3 g) * 100
Calculate:
Percentage by mass ≈ 90.0667%
Therefore, the percentage by mass of water of crystallization in the compound NaCO3XH2O is approximately 90.0667%.