The position of particle moving along x axis is given as a function of time t as x=t^2-4t+7.the distance covered by the particle in first four second is(x is in metre and t is in second). Plzz answer fastly..plzz

X = t^2-4t+7.

X = 4^2 - 4*4 + 7 =

To find the distance covered by the particle in the first four seconds, we need to calculate the displacement of the particle during that time period.

Given the position function x = t^2 - 4t + 7, we can find the displacement by evaluating x at the initial and final times, and then subtracting the two values.

Step-by-step solution:
1. Substitute t = 0 into the position function to find the initial position:
x(0) = (0)^2 - 4(0) + 7
x(0) = 0 - 0 + 7
x(0) = 7

2. Substitute t = 4 into the position function to find the final position:
x(4) = (4)^2 - 4(4) + 7
x(4) = 16 - 16 + 7
x(4) = 7

3. Calculate the displacement by subtracting the initial position from the final position:
Displacement = x(4) - x(0)
Displacement = 7 - 7
Displacement = 0

The distance covered by the particle in the first four seconds is zero meters. This implies that the particle returned to its initial position during this time period.

Note: The distance traveled is always a positive value, while displacement may be zero or any other value (including negative values).