"Calculate the amount of heat (kcal) released when 18.0 g (grams) of steam are condensed at 100.0 C and the resulting water is frozen and cooled to 25.0 C."
The only problem that I'm having is the amount of physical and temperature changes that there are. I'm new and still learning all of this. If anyone could please tell me how many physical and temperature changes there are than I can do the rest on my own (the equations). Thank you!
In this scenario, there are three physical changes and two temperature changes that occur:
1. Physical Change: Condensation of steam at 100.0°C to form water at 100.0°C
2. Physical Change: Freezing of water at 100.0°C to form ice at 0.0°C
3. Physical Change: Cooling of ice at 0.0°C to water at 0.0°C
4. Temperature Change: Cooling of water at 0.0°C to water at 25.0°C
Based on this information, you can now proceed with calculating the amount of heat released at each step using the appropriate equations.
No problem! I'll help you break down the different physical and temperature changes in this problem.
Let's analyze the given information step by step:
1. The initial state of the substance is steam at 100.0°C.
2. The steam is condensed into water. This is a physical change from gas to liquid.
3. The temperature remains constant at 100.0°C during the condensation process.
4. The resulting water then undergoes another physical change: it freezes.
5. The temperature remains constant at the freezing point while the water turns into ice.
6. Finally, the ice is cooled from the freezing point down to 25.0°C.
So, to summarize:
1. Physical change: Gas (steam) to liquid (water) at 100.0°C
2. Physical change: Liquid (water) to solid (ice) at the freezing point
3. Temperature change: Cooling from the freezing point to 25.0°C
Now you can apply the appropriate equations for each step to calculate the amount of heat released. Good luck with the calculations!