Rohan, Amit and Kartik walk around a circular path. Their steps measure 24 cm, 30 cm and 36 cm respectively. How much distance will they cover from the starting point so that they meet again?

LCM(24,30,36) = 360

To find out how much distance Rohan, Amit, and Kartik will cover from the starting point to meet again, we need to find the least common multiple (LCM) of their step lengths.

The step lengths of Rohan, Amit, and Kartik are 24 cm, 30 cm, and 36 cm respectively.

Let's find the LCM of these three numbers.

The prime factorization of 24 is 2^3 * 3.
The prime factorization of 30 is 2 * 3 * 5.
The prime factorization of 36 is 2^2 * 3^2.

To find the LCM, we take the highest power of each prime that appears in the factorization of the numbers. So the LCM is 2^3 * 3^2 * 5 = 360.

Therefore, Rohan, Amit, and Kartik will cover a distance of 360 cm to meet again from the starting point.

To find out how much distance Rohan, Amit, and Kartik will cover before meeting again, we need to determine the least common multiple (LCM) of their step measures.

The step measures are 24 cm, 30 cm, and 36 cm.

To find the LCM, follow these steps:
1. Write the prime factorization of each step measure:

24 = 2^3 * 3^1
30 = 2^1 * 3^1 * 5^1
36 = 2^2 * 3^2

2. Take the highest power of each prime factor that appears in any of the prime factorizations:

Prime factor 2: highest power is 2^3 = 8
Prime factor 3: highest power is 3^2 = 9
Prime factor 5: highest power is 5^1 = 5

3. Multiply the highest powers of each prime factor to get the LCM:

LCM = 2^3 * 3^2 * 5^1 = 8 * 9 * 5 = 360 cm

Therefore, Rohan, Amit, and Kartik will cover a distance of 360 cm before meeting again at the starting point.