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Mathematics
Geometry
Rectangles
Give possible values for length and breadth of rectangle whose area is xsquare-3(x)+2
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x^2-3x+2 = (x-1)(x-2)
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Give possible values for length and breadth of the rectangle whose area is -x square+7x+30
Top answer:
I read that as area = -x^2 + 7x + 30 this has to be positive, so -x^2 + 7x + 30 > 0 x^2 - 7x - 30 <
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the length of a rectangle exceeds its breadth by 4 cm. if length and breadth are each increased by 3 cm, the area of the new
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or - using one variable, as your title suggests width --- x length --- x+4 new width = x+3 new
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1. The lenght of rectangle is greater than its breadth by 2 cm.If the length is increased by 4 cm and the breadth decreased by 3
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L-2=W (L+4)(W-3)=LW check that. So for W, put in L-2, multiply out, and solve for L.
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the length of a rectangle exceeds its breadth by 4cm. The length and breadth are increased by 3 cm .The area of the new
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The length and the breadth of a rectangle are rounded off to the nearest centimetre.The perimeter of the rectangle is 26cm.What
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2 cms by 13 cms
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The length and the breadth of a rectangle are rounded off to the nearest centimetre.The perimeter of the rectangle is 26cm.What
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The length and breadth of a rectangle are in the ration 8:5. The length is 10.5 centimeters more than the breadth. What are the
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(L+10.5)/L=8/5 solve for L first 8L=5L+52.5 3L=52.5 L=17.3 check that. W=that + 10.5
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If the length and breadth of a rectangle are increased by 3m and 2m,respectively the area would increase by 52
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not bad
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the length of a rectangle exceed its breadth by 4cm.if length and breadth are incresed by 3cm the aera of the new reactangle
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now: w and w+4, area = w(w+4) after growth, we have (w+3)(w+4+3) = w(w+3)+81 w^2+10w+21 = w^2+3w+81
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the lenght of rectangle exceeds its breadth are each increased by 3 and the area of the new rectangle is will be 84 cm2 more
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(L+3)(w+3) = 84 + L w L w + 3 L + 3 w + 9 = 84 + L w 3 L + 3 w = 75 need another piece of
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