Calculate molarity of air having malar mass 28.8cotaining N2 and O2 only at 273kelvin and 1atm pressure
To calculate the molarity of air, we first need to determine the number of moles of each gas present in a given volume of air.
The molar mass of air is calculated by considering the molar masses of the individual components (N2 and O2) and their relative quantities. Given that air consists mainly of nitrogen and oxygen and the molar masses of nitrogen (N2) and oxygen (O2) are 28 g/mol and 32 g/mol, respectively:
Molar mass of air = (molar mass of N2 x moles of N2) + (molar mass of O2 x moles of O2)
Let's assume that the mass of air is 28.8 grams. Since air contains only N2 and O2 and both have equal molar masses, we can split the mass equally between them.
Mass of N2 = Mass of O2 = 28.8 g / 2 = 14.4 g
Now, we can find the number of moles of N2 and O2 by dividing their masses by their respective molar masses:
Moles of N2 = Mass of N2 / Molar mass of N2 = 14.4 g / 28 g/mol
Moles of O2 = Mass of O2 / Molar mass of O2 = 14.4 g / 32 g/mol
Next, we need to calculate the volume of air at the given conditions using the ideal gas equation:
PV = nRT
Where:
P = pressure (1 atm)
V = volume (unknown)
n = number of moles of gas
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (273 K)
Rearranging the equation to solve for V:
V = (nRT) / P
Substituting the values:
V = [(moles of N2 + moles of O2) x R x T] / P
Now we can calculate the molarity (moles of gas per unit volume) of air by dividing the total number of moles (moles of N2 + moles of O2) by the volume calculated above:
Molarity = (moles of N2 + moles of O2) / V
Simply plugging in the calculated values will give you the molarity of air at the given conditions.