A constant force acts on a 5.0 kg object and reduces its velocity from 7.0 m/s to 3.0 m/s in a time of 3.0 s. Find the force.
V = Vo + a*t.
3 = 7 + a*3, a = - 1.333 m/s^2.
F = M*a = 5 * (-1.33) = -6.67 N.
The negative sign means that the force opposes the movement of the object.
A constant force acts on a 50 kg object and increases its velocity from 4 m/s to 8 m/s in a time of 4 seconds. Find the Force.
Well, if the force is constant and it's acting on a 5.0 kg object, then we can use Newton's second law which states that force equals mass times acceleration. In this case, the object's mass is 5.0 kg and the acceleration is the change in velocity divided by the change in time. So, the acceleration is (3.0 m/s - 7.0 m/s)/(3.0 s) = -1.33 m/s^2. Now we can plug in the values into the formula: force = mass x acceleration. Therefore, the force is 5.0 kg x (-1.33 m/s^2) = -6.65 N. But we can't have a negative force, that's not allowed! So, let's just say the force is really good at following directions and we'll take the absolute value. That means the force is a whopping 6.65 N!
To find the force, we can use Newton's second law: F = ma, where F is the force, m is the mass of the object, and a is the acceleration.
First, let's find the change in velocity (Δv). We can use the formula: Δv = vf - vi, where vf is the final velocity and vi is the initial velocity.
Δv = 3.0 m/s - 7.0 m/s
Δv = -4.0 m/s
Next, we can find the acceleration (a) using the formula: a = Δv / t, where Δv is the change in velocity and t is the time taken.
a = -4.0 m/s / 3.0 s
a = -1.33 m/s^2
Note: The negative sign indicates that the object is decelerating.
Finally, we can find the force (F) using Newton's second law: F = ma.
F = (5.0 kg) * (-1.33 m/s^2)
F = -6.65 N
So, the force acting on the object is -6.65 N. The negative sign indicates that the force is acting in the opposite direction of motion.
To find the force acting on the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
First, let's find the acceleration of the object. We know that the initial velocity (u) is 7.0 m/s, the final velocity (v) is 3.0 m/s, and the time interval (t) is 3.0 s. The equation that relates these variables is:
v = u + at
Rearranging the equation to solve for acceleration (a), we have:
a = (v - u) / t
Substituting the given values, we get:
a = (3.0 m/s - 7.0 m/s) / 3.0 s
a = -4.0 m/s / 3.0 s
a ≈ -1.33 m/s²
Note that the negative sign indicates that the object is decelerating.
Now, we can calculate the force using Newton's second law. The mass (m) of the object is given as 5.0 kg, and we have already calculated the acceleration (a) as -1.33 m/s². The equation for force (F) is:
F = m * a
Substituting the given values, we get:
F = 5.0 kg * (-1.33 m/s²)
F = -6.65 N
Therefore, the force acting on the 5.0 kg object is approximately -6.65 N. The negative sign indicates that the force is acting in the opposite direction of motion, causing deceleration.