Two equal forces, 20 N each, gives you a resultant value of 20 N. What is the angle between the two forces?
draw the diagram.
Law of cosines:
c^2=a^2+b^2-2abcosTheta where theta is the angle between a and b.
400=400+400-800cosTheta
cosTheta=1/2
Theta= arccos(.5)=60 degrees if I remember correctly.
I think you will find that theta = 120 degrees. the angle used is cos(180-theta)
There is no way that two 20N vectors pointing in basically the same direction can have a resultant of 20N.
You want the short diagonal of the parallelogram.
a 50ml volume of gas is measured at 20 degree celsius,if the pressure remains constant what will be the volume of the gas at 0 degree celsius?
To find the angle between two equal forces, one must use the concept of vector addition and trigonometry.
Given that the forces are equal in magnitude (20 N each) and the resultant value is also 20 N, it indicates that the forces are acting in the same direction. In this case, the angle between the two forces is 0 degrees or they can be considered parallel to each other.
If the forces were acting at an angle other than 0 degrees, the resultant value would be greater than the individual forces. However, since the resultant value is equal to the individual forces, it implies that the forces are acting in the same direction with an angle of 0 degrees.