Calculate normality of 27% H2SO4
Normality =
No. of gram equivalents of H2SO4/ volume of solution (litres)
= (27/49)
-------
100×10^-3
= 5 Normal
Technically I don't think you can work this problem without knowing the specific gravity of the solution. You can assume that the volume of the solution is the same as the mass (0.1 g = 0.1L as Sandu has done which means you assume the density of the solution is 1.00 g/mL) but of course that assumption is not exactly correct. I looked up the specific gravity of a 27.3% H2SO4 solution and found it to be about 1.2 g/mL and that works out to be about 6.6 N. So you replace 100 mL in Sandu's work with 100/1.2 = 83.3 mL or 0.0833 L and (27/49)/(0.0833) = about 6.6 N.
Thank you DrBob222 for the correction..
To calculate the normality of a solution, we need to know the molar concentration of the solute. In this case, we have a 27% H2SO4 solution. The percentage concentration refers to the mass of the solute (in grams) dissolved in 100 mL of solution.
Before we can determine the normality, we need to convert the percentage concentration to molar concentration. To do this, we need to know the molar mass of H2SO4.
The molar mass of H2SO4 is calculated as follows:
2(1.01 g/mol for H) + 32.07 g/mol for S + 4(16.00 g/mol for O) = 98.09 g/mol
Now we can calculate the molarity (M) of H2SO4 using the given percentage concentration:
27% concentration means 27 grams of H2SO4 in 100 mL of solution.
To convert grams to moles, we divide the mass by the molar mass:
27 g H2SO4 × (1 mol H2SO4 / 98.09 g H2SO4) = 0.2758 mol H2SO4
To convert from milliliters (mL) to liters (L), we divide by 1000:
100 mL × (1 L / 1000 mL) = 0.1 L
Now we can calculate the molarity (M) or molar concentration:
Molarity (M) = moles of solute / volume of solution in liters
Molarity (M) = 0.2758 mol / 0.1 L = 2.758 M
Therefore, the molarity or molar concentration of the 27% H2SO4 solution is 2.758 M.
Note: Normality (N) is a measure of the number of equivalents of solute per liter of solution. For a strong acid like H2SO4, the normality is equal to the molarity. So, the normality of the 27% H2SO4 solution is also 2.758 N.