A 100 kg box on the right and a 50 kg box on the left are tied together by a horizontal cable. The 100 kg box is acted upon by an external force of 500 N to the right. The frictional force exerted by the floor on the 100 kg box is 30 N and the frictional force exerted by the floor on the 50 kg box is 20 N. In this problem, orient your axes such that the right direction is positive and the lift direction is negative. What is the net force on the 100 kg block?

To find the net force on the 100 kg block, we need to calculate the total force acting on it.

First, let's calculate the gravitational force on the 100 kg block. The gravitational force can be calculated by using the formula:

Gravitational force = mass × acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2. So, the gravitational force on the 100 kg block is:

Gravitational force = 100 kg × 9.8 m/s^2

Next, let's calculate the frictional force on the 100 kg block. The frictional force is given as 30 N.

Now, let's consider the external force acting on the 100 kg block. According to the problem, an external force of 500 N is applied to the right direction.

Now, let's add up all the forces acting on the block. Since forces in the right direction are considered positive and forces in the left direction are considered negative, the net force can be calculated as the sum of the forces:

Net force = External force - Gravitational force - Frictional force

Substituting the values:

Net force = 500 N - (100 kg × 9.8 m/s^2) - 30 N

Finally, solving the equation will give us the net force on the 100 kg block.