S = 2πr2 + 2πrh solve for h
H=S-2πr/2πr?
Close.
h = (S-2πr^2)/2πr = S/2πr - r
Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
To solve the equation S = 2πr² + 2πrh for h, you need to isolate h on one side of the equation.
Let's break down the equation step by step:
S = 2πr² + 2πrh
First, let's factor out 2πr from the second term on the right side:
S = 2πr(r + h)
Next, isolate (r + h) by dividing both sides of the equation by 2πr:
S / (2πr) = r + h
Now, to isolate h, subtract r from both sides of the equation:
(S / (2πr)) - r = h
So, the solution for h is (S / (2πr)) - r.
Therefore, H = (S - 2πr) / (2πr) is not the correct expression for solving h in terms of S and r. It should be H = (S / (2πr)) - r.
To solve for "h" in the equation S = 2πr^2 + 2πrh, you can follow these steps:
Step 1: Begin with the equation S = 2πr^2 + 2πrh.
Step 2: Group the terms that contain "h" on one side of the equation and the other terms on the other side.
S - 2πr^2 = 2πrh.
Step 3: Divide both sides of the equation by 2πr to isolate "h."
(S - 2πr^2) / (2πr) = h.
Step 4: Simplify if needed and write the final expression for "h."
h = (S - 2πr^2) / (2πr).
Now you have solved for "h" in terms of "S" and "r."