In a titration 100 mL of 3.65 g HCl is added to 200 mL of BA(oh)2 solution of an unknown concentration until the equivalent point find molarity of ba(oh)2
Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O
mols HCl = grams/molar mass = ?
mols Ba(OH)2 = 1/2 that (from the coefficients)
Then M Ba(OH)2 = mols Ba(OH)2/L Ba(OH)2 = ?
To find the molarity of the Ba(OH)2 solution, we need to use the concept of titration and stoichiometry.
1. Write the balanced chemical equation for the reaction between HCl and Ba(OH)2:
2HCl + Ba(OH)2 -> 2H2O + BaCl2
2. Calculate the number of moles of HCl using its molar mass:
moles of HCl = mass of HCl / molar mass of HCl
moles of HCl = 3.65 g / 36.461 g/mol (molar mass of HCl)
3. Use the balanced equation to relate the moles of HCl with the moles of Ba(OH)2.
From the balanced equation, we see that 2 moles of HCl react with 1 mole of Ba(OH)2. Therefore, moles of Ba(OH)2 = moles of HCl / 2.
4. Calculate the volume of the Ba(OH)2 solution in liters:
volume of Ba(OH)2 solution = 200 mL / 1000 mL/L = 0.2 L
5. Calculate the molarity of the Ba(OH)2 solution:
molarity of Ba(OH)2 = moles of Ba(OH)2 / volume of Ba(OH)2 solution
molarity of Ba(OH)2 = (moles of HCl / 2) / 0.2 L
6. Substitute the values and calculate the molarity of Ba(OH)2:
molarity of Ba(OH)2 = (3.65 g / 36.461 g/mol) / 2 / 0.2 L
By following these steps and plugging in the given values, you can determine the molarity of the Ba(OH)2 solution.