Calculate the heat capacity of a sample of radiator coolant if a temperature rise from 5 to 107℃ requires 932 J of heat.
My work:
c=q/mΔT
c=932J/(?)(107℃-5℃)
The problem doesn't tell you the mass of the sample (nor the volume) and density). As is the problem can't be solved.
To calculate the heat capacity of a sample of radiator coolant, you need to know the heat energy absorbed or released by the coolant and the corresponding temperature change.
The formula for heat capacity is:
c = q / (m * ΔT)
Where:
c = heat capacity (J/℃ or J/K)
q = heat energy (J)
m = mass of the coolant (in grams or kilograms)
ΔT = temperature change (in ℃ or K)
In your case, you are given the heat energy (q = 932 J) and the temperature change (ΔT = 107℃ - 5℃ = 102℃). However, you don't have the mass of the coolant (m).
To find the heat capacity, you need to rearrange the formula to solve for mass:
m = q / (c * ΔT)
Since the mass is not provided in the question, we cannot calculate the heat capacity without more information.