A bag contains 9 white 7yellow marbles,8 green marbles. If one marble is drawn from the bag then replaced, what is the probability of drawing a white marble then a

green marble?

p(white) = 9/24 = 3/8

p(green) = 8/24 = 1/3

p(w then g) = 3/8 * 1/3

To calculate the probability of drawing a white marble and then a green marble, you need to consider the number of possible outcomes and the number of favorable outcomes.

Step 1: Calculate the probability of drawing a white marble.
The bag contains a total of 9 white marbles, 7 yellow marbles, and 8 green marbles. Since one marble is drawn and then replaced, the total number of marbles remains the same for each draw. Therefore, the probability of drawing a white marble on the first draw is:
Probability of drawing a white marble = Number of white marbles / Total number of marbles
Probability of drawing a white marble = 9 / (9 + 7 + 8) = 9 / 24 = 3 / 8

Step 2: Calculate the probability of drawing a green marble.
The probability of drawing a green marble on the second draw is the same as the probability of drawing a green marble on the first draw since the marbles are replaced. Therefore, the probability of drawing a green marble is:
Probability of drawing a green marble = Number of green marbles / Total number of marbles
Probability of drawing a green marble = 8 / (9 + 7 + 8) = 8 / 24 = 1 / 3

Step 3: Calculate the probability of both events occurring together.
Since we want both events to occur, we can multiply the probabilities of the individual events:
Probability of drawing a white marble then a green marble = Probability of drawing a white marble × Probability of drawing a green marble
Probability of drawing a white marble then a green marble = (3 / 8) × (1 / 3) = 3 / 24 = 1 / 8

Therefore, the probability of drawing a white marble and then a green marble from the bag is 1/8.