Calculate the normality of solution containing 4g of sodium hydroxide present in 1 litre of solution ?
Normality=Heq*Moles/literssolution
= 1*4/(40*1)=.1N
Normality=weight of substance in gram ×1000/equivalent weight × volume in milliliter
Equivalent weight=molecular mass/xfactor=31/1=31
N=4×1000/31×1000
=4/31
=0.13
To calculate the normality of the solution, we'll need to know the molecular weight of sodium hydroxide (NaOH). The molecular weight of Na = 23 g/mol, O = 16 g/mol, and H = 1 g/mol.
So, NaOH = 23 + 16 + 1 = 40 g/mol.
Next, we calculate the number of moles of NaOH:
Moles = Mass / Molecular Weight
Moles = 4 g / 40 g/mol = 0.1 mol
Now we'll calculate the volume of the solution in liters:
Volume = 1 liter
Finally, we'll calculate the normality of the solution:
Normality = Moles / Volume
Normality = 0.1 mol / 1 L = 0.1 N
Therefore, the normality of the solution containing 4g of sodium hydroxide present in 1 litre of solution is 0.1 N.
To calculate the normality (N) of a solution, you need to know the number of equivalents (Eq) of the solute present in the solution and the volume (V) of the solution in liters. The formula to calculate normality is:
N = Eq / V
In this case, the solute is sodium hydroxide (NaOH). Sodium hydroxide is a strong base that dissociates into sodium ions (Na+) and hydroxide ions (OH-). The chemical equation for this dissociation is:
NaOH → Na+ + OH-
From the equation, we can see that 1 mole of NaOH produces 1 mole of OH-. Thus, the number of equivalents (Eq) of NaOH is equal to the number of moles of NaOH. The molar mass of NaOH is 22.99 g/mol for sodium plus 16.00 g/mol for oxygen plus 1.01 g/mol for hydrogen, giving a total of 39.99 g/mol.
To calculate the number of moles (mol) of NaOH, divide the mass (m) of NaOH by its molar mass (M):
mol = m / M
In this case, the mass of NaOH is 4 g, so the number of moles is:
mol = 4 g / 39.99 g/mol = 0.1 mol
Since 1 mole of NaOH produces 1 mole of OH-, the number of equivalents (Eq) of NaOH is also 0.1 Eq.
Finally, to calculate the normality (N) of the solution, divide the number of equivalents (Eq) by the volume (V) of the solution:
N = Eq / V
In this case, the volume of the solution is 1 liter, so the normality is:
N = 0.1 Eq / 1 L = 0.1 N
Therefore, the normality of the solution containing 4g of sodium hydroxide in 1 liter of solution is 0.1 N.