If a curly haired father and straight haired mother 8 children are born .the ratio of curly and straight haired will be ......
<<Hair type is an interesting case of something called incomplete dominance. What this means is that with hair type, if you have one of each version of the gene, you get a mix of the two or wavy hair. So for hair type, CC gives curly, Cs gives wavy and ss gives straight hair.>>
All children will be Cs, or wavy hair, no curly, no straight.
Now if your teacher does not know this, or perhaps she actually technically did not mean one parent had curly hair, and confused wavy hair as "curly". In that case Wavy and straight gives
Cs vs ss
2Cs
2ss and the ratio of Wavy (Curly?) to straight would be 1:1
To determine the ratio of curly-haired and straight-haired children, we need to consider the possible combinations of genes from the parents.
First, let's assign some letter symbols to represent the hair type genes. Let "C" represent the gene for curly hair and "S" represent the gene for straight hair. Since the father has curly hair (CC) and the mother has straight hair (SS), we can set up a Punnett square to calculate the possible combinations of genes for their children.
Father (Curly) : CC
Mother (Straight): SS
The Punnett square would look like:
| C | C |
-----------------------
| C | CC | CC |
-----------------------
| S | SC | SC |
In this case, all the children would inherit one copy of the curly hair gene (C) from the father and one copy of the straight hair gene (S) from the mother.
So, all the children would have a combination of one curly hair gene (C) and one straight hair gene (S) - making them all carriers of the curly hair gene and expressing straight hair phenotype. Therefore, the ratio of curly-haired to straight-haired children in this family would be 0:8 or 0/8, which simplifies to 0.