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Inverse of h(x)=7-9cos(-(x+1)).

h^-1(x)=? show work please! Thanks.. also accidentally put this as an answer somewhere pls ignore that!

  • math -

    h = 7-9cos(-(x+1))
    9cos(-(x+1)) = 7-h
    cos(-(x+1)) = (7-h)/9
    -(x+1) = arccos((7-h)/9)
    x+1 = -arccos((7-h)/9)
    x = -1-arccos((7-h)/9)

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