math
posted by sophie
Inverse of h(x)=79cos((x+1)).
h^1(x)=? show work please! Thanks.. also accidentally put this as an answer somewhere pls ignore that!

Steve
h = 79cos((x+1))
9cos((x+1)) = 7h
cos((x+1)) = (7h)/9
(x+1) = arccos((7h)/9)
x+1 = arccos((7h)/9)
x = 1arccos((7h)/9)
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