if copper (II) sulfate pentahydrate is known to be 36% of water how many grams of water will be lost when heating a 5.75 grams sample?
5.75 g CuSO4.5H2O ==> CuSO4 + 5H2O
5.75 g x 0.36 = ? g H2O in 5.75 g CuSO4.5H2O
2.07
To find out how many grams of water will be lost when heating a 5.75 gram sample of copper (II) sulfate pentahydrate, we need to calculate the amount of water present in the sample and then determine the loss of water during heating.
First, we need to calculate the amount of water in the sample. Since copper (II) sulfate pentahydrate is known to be 36% water, we can multiply the total mass of the compound by 36% (or 0.36) to find the mass of water:
Mass of water = 5.75 grams * 0.36 = 2.07 grams
Therefore, there are 2.07 grams of water in the 5.75 gram sample of copper (II) sulfate pentahydrate.
During heating, the water molecules will be lost, so the mass of water lost will be 2.07 grams.
To find out how many grams of water will be lost when heating a 5.75 grams sample of copper (II) sulfate pentahydrate, you need to calculate the mass of water in the sample and then determine how much of it will be lost.
First, it is given that copper (II) sulfate pentahydrate contains 36% water. This means that 36% of the mass of copper (II) sulfate pentahydrate comes from water. To calculate the mass of water in the sample, you can simply multiply the total mass of the sample by the percentage of water:
Mass of water = 5.75 grams (sample mass) x 0.36 (36% as a decimal)
Mass of water = 2.07 grams
So, the sample contains 2.07 grams of water.
Next, you need to determine how much water will be lost when heating the sample. Copper (II) sulfate pentahydrate is known to lose all of its water molecules when heated. Therefore, the entire 2.07 grams of water will be lost.
Hence, when heating the 5.75 grams sample of copper (II) sulfate pentahydrate, 2.07 grams of water will be lost.