polynomials
posted by sara .
I have to simplify
(x^5y^4)^4(3x^2y)^2(1/3xy)
I did
(x^20y^16)(9x^4y^2)(1/3xy)
(9x^24y^18)(1/3xy)
3x^25y^19
Is this correct?
Thank you for your help!

First of all, it's not a polynomial,as there is only one term.
It's ok to here:
(9x^24y^18)(1/3xy)
Now, is that 1/(3xy) or (1/3)xy ?
It appears that you meant (1/3) xy, but it's hard to say, since you some how got
(...)(1/3) = 3(...)
How did you manage to switch from dividing to multiplying by 3?
So, if you meant (1/3) xy, the answer is 1/3 3x^25y^19
If it was 1/(3xy), then you have
1/3 x^23y^17
In either case, you can't switch 1/3 to 3.
Now, if you meant
(...)/(1/3xy)
then you get a 3 in front, since you are dividing by 1/3. 
Thank you for explaining my mistake.
Respond to this Question
Similar Questions

bobpursly,
Is this correct now after i revised it Multiply. 3xy^2(5xy4x+6y) 3xy^2(5xy)=15x^2y^3 3xy^2(4x)=12x^2y^2 3xy^2(6y)=18xy^3 so i get from this 15x^2y^312x^2y^2+18xy^3 correct awsome i just thought that the 15x^2y^312x^2y^2 should … 
Math
I have no clue how to do this as no values were given and im confused. can someone explain plz? 
AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? 
AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? 
Math
How do you factor: 9x^2y^3  3x^3y^2  15xy i got: 3xy(3xy^2  x^2y  5) But how do you factor it further to simplify it? 
Derive
Find the derivative of sin(2x + 3y)= 3xy + 5y2. I have this so far 1) cos(2x+3y) * d/dx (2x+3y)= 3xy' + 3y + 5y' 2) cos (2x+3y) * [2 + 3y']= 3xy' + 3y + 5y' 3) 3y' cos (2x+3y) + 2cos(2x+3y)= 3xy' + 3y + 5y' 4) 3xy' + 5y'  (3y(cos(3x+3y)= … 
Math help polynomial
multiply the following polynomial 3x(y^2+2y^2) answer choices 3xy^26xy^2' 3xy^2gxy^2 3xy^2+5y^2 9xy^2 The last one was the answer. Can you tell me how the answer was solved? 
Math!
1) What is the value of 19 + 5a^4 + 3b^2 when a = 2 and b = 4? 
algebra
Simplify. Do not use negative exponents in the answer. 12x2y4 3xy7 There should be a line between like a fraction but it did not copy or paste. This is the answer I got 12 x^2 y^4 = 12y^4/x^2 3xy^7 = 3x/y^7 it was wrong. 12x^2y^4 … 
Simultaneous equation
X+y+z=1......(1) x^2+y^2+z^2=35........(2) x^3+y^3+z^3=97.........(3) solution but from 3 (x^3+y^3)=(x+y)^33xy(x+y)......(4) puting 4 into 3 bck (x+y)^33xy(x+y)+z^3=97.......(5) now from 1 x+y=1z......(6) putin 6 into 7 we have …