A ball is thrown straight down with a velocity of 12 m/s; what will be its velocity 2.0 s after being released? Please help me solve this!!
To solve this problem, we need to consider the effect of gravity on the ball's velocity.
When the ball is thrown straight down, its initial velocity is 12 m/s. Due to the force of gravity, its velocity will increase at a rate of 9.8 m/s^2 (acceleration due to gravity).
To find the ball's velocity 2.0 s after being released, we can use the following equation:
v = u + at
Where:
- v is the final velocity
- u is the initial velocity
- a is the acceleration
- t is the time
Substituting the given values into the equation:
v = 12 m/s + (9.8 m/s^2)(2.0 s)
Calculating:
v = 12 m/s + (19.6 m/s)
v = 31.6 m/s
Therefore, the ball's velocity 2.0 s after being released will be 31.6 m/s.
To solve this problem, we can use the equation for velocity as a function of time:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given in the problem that the ball is thrown straight down, we can assume that the acceleration due to gravity is acting on it. This acceleration is approximately 9.8 m/s², and since the ball is thrown downwards, we take it as a negative value.
From the given data:
u = -12 m/s (negative because it is thrown downwards)
t = 2.0 s
a = -9.8 m/s²
Now we can substitute the values into the equation:
v = -12 m/s + (-9.8 m/s²) * 2.0 s
Multiply -9.8 m/s² by 2.0 s:
v = -12 m/s - 19.6 m/s
Simplifying, we get:
v = -31.6 m/s
Therefore, the velocity of the ball 2.0 s after being released will be -31.6 m/s. The negative sign indicates that it is moving downwards.