if, instead of assuming that the mean body temperature is 98.20 degree Ferinheight, we assume that the mean is 98.60 F(as many people believe), wht is the chance of randomly selecting 106 people and getting a mean of 98.20 degree F or lower? (continue to assume that the standard deviation is 0.62 F. University of Maryland researchers id get such a result. what should we conclude?.

Question

if, instead of assuming that the mean body temperature is 98.20 degree Ferinheight, we assume that the mean is 98.60 F(as many people believe), wht is the chance of randomly selecting 106 people and getting a mean of 98.20 degree F or lower? (continue to assume that the standard deviation is 0.62 F. University of Maryland researchers id get such a result. what should we conclude?.

Answer 1

Z = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

Conclusion would be related to level of significance you are using.