Let A = (1,2,5) B = {1,2,4,5,6,8} and the relation R is "less than or equal to."Representing the relation BRA in set gives???
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To represent the relation R in set form, we need to identify the ordered pairs that satisfy the relation. In this case, the relation R is "less than or equal to," so we need to find the pairs where the first element is less than or equal to the second element.
Given set A = {1, 2, 5} and set B = {1, 2, 4, 5, 6, 8}, we can create the ordered pairs by combining each element from A with each element from B. The resulting pairs will be:
(1, 1), (1, 2), (1, 4), (1, 5), (1, 6), (1, 8)
(2, 1), (2, 2), (2, 4), (2, 5), (2, 6), (2, 8)
(5, 1), (5, 2), (5, 4), (5, 5), (5, 6), (5, 8)
Now we can analyze each pair and check if the first element is less than or equal to the second element:
(1, 1) - True
(1, 2) - True
(1, 4) - True
(1, 5) - True
(1, 6) - True
(1, 8) - True
(2, 1) - False
(2, 2) - True
(2, 4) - True
(2, 5) - True
(2, 6) - True
(2, 8) - True
(5, 1) - False
(5, 2) - False
(5, 4) - False
(5, 5) - True
(5, 6) - True
(5, 8) - True
Finally, we can collect the pairs where the first element is less than or equal to the second element to represent the relation R in set form:
R = {(1, 1), (1, 2), (1, 4), (1, 5), (1, 6), (1, 8), (2, 2), (2, 4), (2, 5), (2, 6), (2, 8), (5, 5), (5, 6), (5, 8)}
So, the relation R, represented in set form, is R = {(1, 1), (1, 2), (1, 4), (1, 5), (1, 6), (1, 8), (2, 2), (2, 4), (2, 5), (2, 6), (2, 8), (5, 5), (5, 6), (5, 8)}.