Father is aged three times more than his son Ronti. After 8 years , he would be two and a half times of Ronti's age. After further 8 years, how many times would he be of Ronti's age?

f = 3r

f+8 = 5/2 (r+8)

r=24, so f=72
check: (72+8)/(24+8) = 80/32 = 5/2

So, (72+16)/(24+16) = 88/40 = 11/5

To find out how many times the father would be of Ronti's age in the future, we need to determine their present ages and calculate the ratio of their ages.

Let's assume Ronti's present age is 'x'.
According to the first statement, the father's age is three times more than Ronti's. Therefore, the father's age is 3x.

After 8 years, Ronti's age will be x + 8, and the father's age will be 3x + 8.
Based on the second statement, the father's age after 8 years would be two and a half times Ronti's age:
3x + 8 = 2.5 * (x + 8)

Simplifying the equation:
3x + 8 = 2.5x + 20
0.5x = 12
x = 24

So, Ronti's present age is 24, and the father's present age is 3 * 24 = 72.

After another 8 years, Ronti's age will be 24 + 8 = 32.
The father's age after another 8 years will be 72 + 8 = 80.

Now, we can find out how many times the father's age is of Ronti's age:
80 / 32 = 2.5

Therefore, the father would be 2.5 times Ronti's age after a further 8 years.