Please help...entrance exam soon
Write the oxidation and reduction half reactions(showing e- lost or gained) for the foll
O3 + I- -> IO3- + O2 (acidic)
IO3^- + 3H2O ==> IO3^- + 6e + 6H^+
O3 + 2H^+ +2e ==> O2 + H2O
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You can get the molecular equation by multiplying equn 1 by 1 and eqn 2 by 3, then cancel ions common to both sides and you end up with this.
3O3 + I^- ==> 3O2 + IO3^-