Ron has a piece of rope 6 1/2 long,Tony has one that is 7 2/3m long.How long are their ropes if put together?
To find the total length of Ron and Tony's ropes when put together, we need to add the lengths of their ropes.
Ron's rope length = 6 1/2 m
Tony's rope length = 7 2/3 m
First, let's convert the mixed fractions into improper fractions:
Ron's rope length = 6 1/2 m = (6 * 2 + 1) / 2 m = 13/2 m
Tony's rope length = 7 2/3 m = (7 * 3 + 2) / 3 m = 23/3 m
Now, add the lengths of their ropes:
Total length = Ron's rope length + Tony's rope length
Total length = 13/2 m + 23/3 m
To add fractions, we need to have a common denominator. The least common multiple (LCM) of 2 and 3 is 6.
Total length = (13/2 * 3/3) m + (23/3 * 2/2) m
Total length = 39/6 m + 46/6 m
Now, add the numerators:
Total length = (39 + 46) / 6 m
Total length = 85/6 m
The total length of their ropes when put together is 85/6 meters.
To find the total length of the two ropes, we need to add the lengths of Ron's rope and Tony's rope.
Ron's rope is 6 1/2 meters long, which can be written as a mixed number: 6 + 1/2 = 6 1/2 = 13/2.
Tony's rope is 7 2/3 meters long, which can also be written as a mixed number: 7 + 2/3 = 7 2/3 = 23/3.
To add the lengths of the two ropes, we need to find a common denominator for the fractions. The least common multiple of 2 and 3 is 6, so we can rewrite the fractions with a denominator of 6:
Ron's rope: 13/2 = 39/6
Tony's rope: 23/3 = 46/6
Now, we can add the two fractions:
39/6 + 46/6 = (39 + 46)/6 = 85/6
Therefore, the total length of the two ropes when put together is 85/6 meters.
That's the answer
6 1/2 + 7 2/3
= 6 3/6 + 7 4/6
= ...