The spinner below is used in a game, if you spin the spinner once what is the probability that it will land on a multiple of 3 or an even number

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To determine the probability of the spinner landing on a multiple of 3 or an even number, we need to consider the number of favorable outcomes and the total number of possible outcomes.

Let's analyze the spinner first. Although you mentioned a spinner below, I can't see or visualize it. However, assuming it is a standard spinner with numbers from 1 to 6 arranged evenly, we can assess the situation.

Now, consider the favorable outcomes, which are the numbers that satisfy the condition of being either a multiple of 3 or an even number.

Multiples of 3: 3 and 6
Even numbers: 2, 4, and 6

To avoid double counting 6, we only count it once. Therefore, we have a total of 5 favorable outcomes (3, 6, 2, 4, and 6).

Next, we need to determine the total number of possible outcomes. In this case, since the spinner has numbers from 1 to 6, there are 6 possible outcomes.

So, the probability of the spinner landing on a multiple of 3 or an even number can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes:

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
Probability = 5 / 6

So, the probability that the spinner will land on a multiple of 3 or an even number is 5/6 or approximately 0.8333.