A joggler throws an apple vertically upward just enough to reach the ceiling exactly 4 meters from the jogglers hand . What is the initial velocity of the apple ?
To find the initial velocity of the apple, we can use the equation of motion for vertical motion:
v^2 = u^2 + 2as
Where:
v = final velocity (which is zero when the apple reaches its maximum height)
u = initial velocity (what we want to find)
a = acceleration due to gravity (-9.8 m/s^2, assuming no air resistance)
s = distance traveled upwards (4 meters)
Since the final velocity is zero at the maximum height, we can simplify the equation as follows:
0^2 = u^2 + 2*(-9.8)*4
0 = u^2 - 78.4
Rearranging the equation, we have:
u^2 = 78.4
Taking the square root of both sides, we find:
u = sqrt(78.4) ≈ 8.85 m/s
Therefore, the initial velocity of the apple is approximately 8.85 m/s.